November 12, 2023
题2
#

#include <stdio.h>
#include <math.h>
int main()
{
float f,x;
printf("请输入一个数\n");
scanf("%f",&x);
switch ((int)(x/1)) {
case 0:
f=0;
break;
case 1:
f=3*x+5;
break;
case 2:
f=3*sin(x)-1;
break;
case 3:
f=log(1+x*x);
break;
case 4:
f=log10(x*x-2*x)+5;
break;
default:
f=-1;
break;
}
printf("输入:%f,结果:%f",x,f);
}
题3
#

#include <stdio.h>
int main()
{
float g,n;
float m=0;
printf("请输入重量\n");
scanf("%f",&g);
if(g>50) {
printf("拒收");
return 0;
}
n=g;
switch ((int)g/5) {
case 10:
case 9:
case 8:
case 7:
case 6:
m+=5.0*(g-30);
g=30;
case 5:
case 4:
m+=4.5*(g-20);
g=20;
case 3:
case 2:
m+=4.0*(g-10);
g=10;
case 1:
m+=3.5*(g-5);
g=5;
case 0:
m+=3.0*g;
break;
default:
m=-1;
break;
}
printf("重量:%.2fkg,快递费:%.2f",n,m);
}
October 23, 2023
编程题7
#
#include <stdio.h>
int main() {
int num, a, b, c, d;
printf("请输入一个四位数:");
scanf("%d", &num);
if (num >= 1000 && num <= 9999) {
a = num % 10;
b = num / 100 % 10;
c = num / 10 % 10;
d = num / 1000;
printf("个位:%d,十位:%d,百位:%d,千位:%d", a, c, b, d);
} else {
printf("重新输入");
}
return 0;
}
编程题8
#
#include <stdio.h>
#define PAI 3.1415926
int main()
{
int r;
printf("请输入半径:");
scanf("%d",&r);
printf("圆的半径=%d, 圆的直径=%d, 圆的周长=%.2f",
r,
2*r,
PAI*r*2
);
return 0;
}
编程题9
#
#include <stdio.h>
#define PAI 3.1415926
int main()
{
int r;
printf("请输入半径:");
scanf("%d",&r);
printf("半径=%d, 周长=%.2f, 面积=%.2f",
r,
2* PAI*r,
PAI*r*r
);
return 0;
}
编程题11
#
#include <stdio.h>
#include <math.h>
int main()
{
double a=3,b=4,c=6;
double p,s;
if (a+b>c && a+c>b && b+c>a)
{
p=(a+b+c)/2;
s= sqrt (p*(p-a)*(p-b)*(p-c));
printf ( "面积为%lf\n" , s);
}
else printf ( "无法构成三角形\n" );
return 0;
}
编程题12
#
#include <stdio.h>
#include <math.h>
int main()
{
int a,b;
puts("请输入两个整数");
scanf("%d,%d",&a,&b);
printf("和=%d,差=%d,积=%d,商=%.2f,余数=%d",
a+b,
a-b,
a*b,
a/(float)b,
a%b
);
}
编程题13
#
#include <stdio.h>
#include <math.h>
#define PAI 3.1415926
//圆面积
#define get_round_area(r) PAI * r * r
//圆周长
#define get_round_perimeter(r) 2 * PAI * r
//球体表面积
#define get_sphere_Sarea(r) 4 * PAI * r *4 * PAI* r
//球体体积
#define get_sphere_volume(r) 4.0 / 3 * PAI * r * r * r
//圆柱体积
#define get_cylinder_vloume(r,h) get_round_area(r) * h
int main() {
float r,h;
printf("请输入圆的半径和圆柱的高\n");
scanf("%f,%f",&r,&h);
printf("半径=%.2f,周长=%.2f,面积=%.2f,圆球表面积=%.2f,圆球体积=%.2f,圆柱体积=%.2f",
r,
get_round_perimeter(r),
get_round_area(r),
get_sphere_Sarea(r),
get_sphere_volume(r),
get_cylinder_vloume(r,h)
);
return 0;
}
编程题14
#
#include <stdio.h>
#define PAI 3.1415926
int main()
{
int r;
puts("请输入半径");
scanf("%d",&r);
printf("直径=%d, 周长=%.2f",2*r,PAI*r*2);
return 0;
}
编程题15
#
#include <stdio.h>
int main()
{
int a,b;
puts("请输入两个整数");
scanf("%d,%d",&a,&b);
printf("a=%d, b=%d",a,b);
return 0;
}
编程题16
#

...
October 23, 2023
C语言旋转甜甜圈
#include <stdio.h>
#include <math.h>
#include <cstring>
#include <Windows.h>
void usleep(__int64 usec)
{
HANDLE timer;
LARGE_INTEGER ft;
ft.QuadPart = -(10 * usec);
timer = CreateWaitableTimer(NULL, TRUE, NULL);
SetWaitableTimer(timer, &ft, 0, NULL, NULL, 0);
WaitForSingleObject(timer, INFINITE);
CloseHandle(timer);
}
int main() {
float A = 0, B = 0;
float i, j;
int k;
float z[1760];
char b[1760];
printf("\x1b[2J");
for (;;) {
memset(b, 32, 1760);
memset(z, 0, 7040);
for (j = 0; j < 6.28; j += 0.07) {
for (i = 0; i < 6.28; i += 0.02) {
float c = sin(i);
float d = cos(j);
float e = sin(A);
float f = sin(j);
float g = cos(A);
float h = d + 2;
float D = 1 / (c * h * e + f * g + 5);
float l = cos(i);
float m = cos(B);
float n = sin(B);
float t = c * h * g - f * e;
int x = 40 + 30 * D * (l * h * m - t * n);
int y = 12 + 15 * D * (l * h * n + t * m);
int o = x + 80 * y;
int N = 8 * ((f * e - c * d * g) * m - c * d * e - f * g - l * d * n);
if (22 > y && y > 0 && x > 0 && 80 > x && D > z[o]) {
z[o] = D;
b[o] = ".,-~:;=!*#$@"[N > 0 ? N : 0];
}
}
}
printf("\x1b[H");
for (k = 0; k < 1761; k++) {
putchar(k % 80 ? b[k] : 10);
A += 0.00004;
B += 0.00002;
}
usleep(30000);
}
return 0;
}
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